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someone good at algebra???...


Guest WREK

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5 - w[5-(5-w)]

 

okay, start by removing the inner parentheses and distribute the minus sign:

 

= 5 - w[5-5+w]

 

Next remove the brackets and distribute the -w:

 

5 - 5w + 5w - w^2 (thats "w-squared")

 

now the two 5w's go away since one is pos and one is neg :

 

5 - w^2

 

for the next problem you posted, i need to know what variable you're solving for: w or C?

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allright i'm almost off and about to go home, so i'll help you solve the equation:

 

A = 5w+C/2

 

If you're solving for w:

 

first switch the sides of C/2:

 

A - C/2 = 5w

 

next divide both sides by 5:

 

(A - C/2)/5 = 5w/5

 

rewrite as:

 

A/5 - C/(2X5) = 5

 

rewrite:

 

A/5 - C/10 = 5

 

 

 

If you're solving for C:

 

A = 5w+C/2

 

Switch sides for 5w:

 

A - 5W = C/2

 

multiply both sides by 2:

 

2(A - 5W) = 2C/2

 

Distribute the two on the left hand side, and cancel the two on the right hand side:

 

2A -10W = C

 

Hope this helped...

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Guest -MOE LESTER-

im a junior in high school and i have absolutely no idea how to solve those problems!!! i kno alot about world war II though!

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